4(3x-8)+7=19-12(3x-1)

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Solution for 4(3x-8)+7=19-12(3x-1) equation: 



4(3x-8)+7=19-12(3x-1)

We move all terms to the left:

4(3x-8)+7-(19-12(3x-1))=0

We multiply parentheses

12x-(19-12(3x-1))-32+7=0



We calculate terms in parentheses: -(19-12(3x-1)), so:

19-12(3x-1)

determiningTheFunctionDomain
-12(3x-1)+19

We multiply parentheses

-36x+12+19

We add all the numbers together, and all the variables

-36x+31

Back to the equation:

-(-36x+31)



We add all the numbers together, and all the variables

12x-(-36x+31)-25=0

We get rid of parentheses

12x+36x-31-25=0

We add all the numbers together, and all the variables

48x-56=0

We move all terms containing x to the left, all other terms to the right

48x=56

x=56/48

x=1+1/6

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