4(3x-7)+20=-6x+12

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Solution for 4(3x-7)+20=-6x+12 equation: 



4(3x-7)+20=-6x+12

We move all terms to the left:

4(3x-7)+20-(-6x+12)=0

We multiply parentheses

12x-(-6x+12)-28+20=0

We get rid of parentheses

12x+6x-12-28+20=0

We add all the numbers together, and all the variables

18x-20=0

We move all terms containing x to the left, all other terms to the right

18x=20

x=20/18

x=1+1/9

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