4(3x-6)-2=4(x-5)+10

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Solution for 4(3x-6)-2=4(x-5)+10 equation:



4(3x-6)-2=4(x-5)+10
We move all terms to the left:
4(3x-6)-2-(4(x-5)+10)=0
We multiply parentheses
12x-(4(x-5)+10)-24-2=0
We calculate terms in parentheses: -(4(x-5)+10), so:
4(x-5)+10
We multiply parentheses
4x-20+10
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
We add all the numbers together, and all the variables
12x-(4x-10)-26=0
We get rid of parentheses
12x-4x+10-26=0
We add all the numbers together, and all the variables
8x-16=0
We move all terms containing x to the left, all other terms to the right
8x=16
x=16/8
x=2

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