4(3x-5)=6x+(13+x)

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Solution for 4(3x-5)=6x+(13+x) equation: 



4(3x-5)=6x+(13+x)

We move all terms to the left:

4(3x-5)-(6x+(13+x))=0

We add all the numbers together, and all the variables

4(3x-5)-(6x+(x+13))=0

We multiply parentheses

12x-(6x+(x+13))-20=0



We calculate terms in parentheses: -(6x+(x+13)), so:

6x+(x+13)

We get rid of parentheses

6x+x+13

We add all the numbers together, and all the variables

7x+13

Back to the equation:

-(7x+13)



We get rid of parentheses

12x-7x-13-20=0

We add all the numbers together, and all the variables

5x-33=0

We move all terms containing x to the left, all other terms to the right

5x=33

x=33/5

x=6+3/5

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