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4(3x-5)=2x+5(2x-4)
We move all terms to the left:
4(3x-5)-(2x+5(2x-4))=0
We multiply parentheses
12x-(2x+5(2x-4))-20=0
We calculate terms in parentheses: -(2x+5(2x-4)), so:We get rid of parentheses
2x+5(2x-4)
We multiply parentheses
2x+10x-20
We add all the numbers together, and all the variables
12x-20
Back to the equation:
-(12x-20)
12x-12x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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