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4(3x-5)-1=3-4(x-6)
We move all terms to the left:
4(3x-5)-1-(3-4(x-6))=0
We multiply parentheses
12x-(3-4(x-6))-20-1=0
We calculate terms in parentheses: -(3-4(x-6)), so:We add all the numbers together, and all the variables
3-4(x-6)
determiningTheFunctionDomain -4(x-6)+3
We multiply parentheses
-4x+24+3
We add all the numbers together, and all the variables
-4x+27
Back to the equation:
-(-4x+27)
12x-(-4x+27)-21=0
We get rid of parentheses
12x+4x-27-21=0
We add all the numbers together, and all the variables
16x-48=0
We move all terms containing x to the left, all other terms to the right
16x=48
x=48/16
x=3
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