4(3x-40)=68

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Solution for 4(3x-40)=68 equation: 



4(3x-40)=68

We move all terms to the left:

4(3x-40)-(68)=0

We multiply parentheses

12x-160-68=0

We add all the numbers together, and all the variables

12x-228=0

We move all terms containing x to the left, all other terms to the right

12x=228

x=228/12

x=19

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