4(3x-4)+10=68

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Solution for 4(3x-4)+10=68 equation: 



4(3x-4)+10=68

We move all terms to the left:

4(3x-4)+10-(68)=0

We add all the numbers together, and all the variables

4(3x-4)-58=0

We multiply parentheses

12x-16-58=0

We add all the numbers together, and all the variables

12x-74=0

We move all terms containing x to the left, all other terms to the right

12x=74

x=74/12

x=6+1/6

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