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4(3x-3)=5(2x-2)
We move all terms to the left:
4(3x-3)-(5(2x-2))=0
We multiply parentheses
12x-(5(2x-2))-12=0
We calculate terms in parentheses: -(5(2x-2)), so:We get rid of parentheses
5(2x-2)
We multiply parentheses
10x-10
Back to the equation:
-(10x-10)
12x-10x+10-12=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1
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