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4(3x-3)=3(3x+5)
We move all terms to the left:
4(3x-3)-(3(3x+5))=0
We multiply parentheses
12x-(3(3x+5))-12=0
We calculate terms in parentheses: -(3(3x+5)), so:We get rid of parentheses
3(3x+5)
We multiply parentheses
9x+15
Back to the equation:
-(9x+15)
12x-9x-15-12=0
We add all the numbers together, and all the variables
3x-27=0
We move all terms containing x to the left, all other terms to the right
3x=27
x=27/3
x=9
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