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4(3x-3)+49=6x+1
We move all terms to the left:
4(3x-3)+49-(6x+1)=0
We multiply parentheses
12x-(6x+1)-12+49=0
We get rid of parentheses
12x-6x-1-12+49=0
We add all the numbers together, and all the variables
6x+36=0
We move all terms containing x to the left, all other terms to the right
6x=-36
x=-36/6
x=-6
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