4(3x-2)=6x+4x-18

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Solution for 4(3x-2)=6x+4x-18 equation: 



4(3x-2)=6x+4x-18

We move all terms to the left:

4(3x-2)-(6x+4x-18)=0

We add all the numbers together, and all the variables

4(3x-2)-(10x-18)=0

We multiply parentheses

12x-(10x-18)-8=0

We get rid of parentheses

12x-10x+18-8=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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