4(3x-2)=6(x-3)-8

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Solution for 4(3x-2)=6(x-3)-8 equation: 



4(3x-2)=6(x-3)-8

We move all terms to the left:

4(3x-2)-(6(x-3)-8)=0

We multiply parentheses

12x-(6(x-3)-8)-8=0



We calculate terms in parentheses: -(6(x-3)-8), so:

6(x-3)-8

We multiply parentheses

6x-18-8

We add all the numbers together, and all the variables

6x-26

Back to the equation:

-(6x-26)



We get rid of parentheses

12x-6x+26-8=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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