4(3x-2)=6(x+10)

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Solution for 4(3x-2)=6(x+10) equation: 



4(3x-2)=6(x+10)

We move all terms to the left:

4(3x-2)-(6(x+10))=0

We multiply parentheses

12x-(6(x+10))-8=0



We calculate terms in parentheses: -(6(x+10)), so:

6(x+10)

We multiply parentheses

6x+60

Back to the equation:

-(6x+60)



We get rid of parentheses

12x-6x-60-8=0

We add all the numbers together, and all the variables

6x-68=0

We move all terms containing x to the left, all other terms to the right

6x=68

x=68/6

x=11+1/3

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