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4(3x-2)=2(x+6)
We move all terms to the left:
4(3x-2)-(2(x+6))=0
We multiply parentheses
12x-(2(x+6))-8=0
We calculate terms in parentheses: -(2(x+6)), so:We get rid of parentheses
2(x+6)
We multiply parentheses
2x+12
Back to the equation:
-(2x+12)
12x-2x-12-8=0
We add all the numbers together, and all the variables
10x-20=0
We move all terms containing x to the left, all other terms to the right
10x=20
x=20/10
x=2
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