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4(3x-2)=2(x+1)
We move all terms to the left:
4(3x-2)-(2(x+1))=0
We multiply parentheses
12x-(2(x+1))-8=0
We calculate terms in parentheses: -(2(x+1)), so:We get rid of parentheses
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
12x-2x-2-8=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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