4(3x-2)=12(x+1)

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Solution for 4(3x-2)=12(x+1) equation:


Simplifying
4(3x + -2) = 12(x + 1)

Reorder the terms:
4(-2 + 3x) = 12(x + 1)
(-2 * 4 + 3x * 4) = 12(x + 1)
(-8 + 12x) = 12(x + 1)

Reorder the terms:
-8 + 12x = 12(1 + x)
-8 + 12x = (1 * 12 + x * 12)
-8 + 12x = (12 + 12x)

Add '-12x' to each side of the equation.
-8 + 12x + -12x = 12 + 12x + -12x

Combine like terms: 12x + -12x = 0
-8 + 0 = 12 + 12x + -12x
-8 = 12 + 12x + -12x

Combine like terms: 12x + -12x = 0
-8 = 12 + 0
-8 = 12

Solving
-8 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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