4(3x-2)=(6x+1)

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Solution for 4(3x-2)=(6x+1) equation: 



4(3x-2)=(6x+1)

We move all terms to the left:

4(3x-2)-((6x+1))=0

We multiply parentheses

12x-((6x+1))-8=0



We calculate terms in parentheses: -((6x+1)), so:

(6x+1)

We get rid of parentheses

6x+1

Back to the equation:

-(6x+1)



We get rid of parentheses

12x-6x-1-8=0

We add all the numbers together, and all the variables

6x-9=0

We move all terms containing x to the left, all other terms to the right

6x=9

x=9/6

x=1+1/2

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