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4(3x-2)+3=-(4-7x)
We move all terms to the left:
4(3x-2)+3-(-(4-7x))=0
We add all the numbers together, and all the variables
4(3x-2)-(-(-7x+4))+3=0
We multiply parentheses
12x-(-(-7x+4))-8+3=0
We calculate terms in parentheses: -(-(-7x+4)), so:We add all the numbers together, and all the variables
-(-7x+4)
We get rid of parentheses
7x-4
Back to the equation:
-(7x-4)
12x-(7x-4)-5=0
We get rid of parentheses
12x-7x+4-5=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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