4(3x-2)+2x=2(6-x)-4

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Solution for 4(3x-2)+2x=2(6-x)-4 equation:



4(3x-2)+2x=2(6-x)-4
We move all terms to the left:
4(3x-2)+2x-(2(6-x)-4)=0
We add all the numbers together, and all the variables
4(3x-2)+2x-(2(-1x+6)-4)=0
We add all the numbers together, and all the variables
2x+4(3x-2)-(2(-1x+6)-4)=0
We multiply parentheses
2x+12x-(2(-1x+6)-4)-8=0
We calculate terms in parentheses: -(2(-1x+6)-4), so:
2(-1x+6)-4
We multiply parentheses
-2x+12-4
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
We add all the numbers together, and all the variables
14x-(-2x+8)-8=0
We get rid of parentheses
14x+2x-8-8=0
We add all the numbers together, and all the variables
16x-16=0
We move all terms containing x to the left, all other terms to the right
16x=16
x=16/16
x=1

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