4(3x-2)+2x-4=12

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Solution for 4(3x-2)+2x-4=12 equation: 



4(3x-2)+2x-4=12

We move all terms to the left:

4(3x-2)+2x-4-(12)=0

We add all the numbers together, and all the variables

2x+4(3x-2)-16=0

We multiply parentheses

2x+12x-8-16=0

We add all the numbers together, and all the variables

14x-24=0

We move all terms containing x to the left, all other terms to the right

14x=24

x=24/14

x=1+5/7

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