4(3x-2)+2=3(4x-2)

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Solution for 4(3x-2)+2=3(4x-2) equation: 



4(3x-2)+2=3(4x-2)

We move all terms to the left:

4(3x-2)+2-(3(4x-2))=0

We multiply parentheses

12x-(3(4x-2))-8+2=0



We calculate terms in parentheses: -(3(4x-2)), so:

3(4x-2)

We multiply parentheses

12x-6

Back to the equation:

-(12x-6)



We add all the numbers together, and all the variables

12x-(12x-6)-6=0

We get rid of parentheses

12x-12x+6-6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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