4(3x-1)=7x-40

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Solution for 4(3x-1)=7x-40 equation: 



4(3x-1)=7x-40

We move all terms to the left:

4(3x-1)-(7x-40)=0

We multiply parentheses

12x-(7x-40)-4=0

We get rid of parentheses

12x-7x+40-4=0

We add all the numbers together, and all the variables

5x+36=0

We move all terms containing x to the left, all other terms to the right

5x=-36

x=-36/5

x=-7+1/5

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