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4(3x-1)=2(x+13)
We move all terms to the left:
4(3x-1)-(2(x+13))=0
We multiply parentheses
12x-(2(x+13))-4=0
We calculate terms in parentheses: -(2(x+13)), so:We get rid of parentheses
2(x+13)
We multiply parentheses
2x+26
Back to the equation:
-(2x+26)
12x-2x-26-4=0
We add all the numbers together, and all the variables
10x-30=0
We move all terms containing x to the left, all other terms to the right
10x=30
x=30/10
x=3
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