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4(3x-1)-(6x-5)=5x-2(x-1)
We move all terms to the left:
4(3x-1)-(6x-5)-(5x-2(x-1))=0
We multiply parentheses
12x-(6x-5)-(5x-2(x-1))-4=0
We get rid of parentheses
12x-6x-(5x-2(x-1))+5-4=0
We calculate terms in parentheses: -(5x-2(x-1)), so:We add all the numbers together, and all the variables
5x-2(x-1)
We multiply parentheses
5x-2x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
6x-(3x+2)+1=0
We get rid of parentheses
6x-3x-2+1=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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