4(3x-1)+3(2x+6)=4(4x+1)

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Solution for 4(3x-1)+3(2x+6)=4(4x+1) equation: 



4(3x-1)+3(2x+6)=4(4x+1)

We move all terms to the left:

4(3x-1)+3(2x+6)-(4(4x+1))=0

We multiply parentheses

12x+6x-(4(4x+1))-4+18=0



We calculate terms in parentheses: -(4(4x+1)), so:

4(4x+1)

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We add all the numbers together, and all the variables

18x-(16x+4)+14=0

We get rid of parentheses

18x-16x-4+14=0

We add all the numbers together, and all the variables

2x+10=0

We move all terms containing x to the left, all other terms to the right

2x=-10

x=-10/2

x=-5

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