4(3x+x)+7-5x=8+-5(5x-6)+23

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Solution for 4(3x+x)+7-5x=8+-5(5x-6)+23 equation: 



4(3x+x)+7-5x=8+-5(5x-6)+23

We move all terms to the left:

4(3x+x)+7-5x-(8+-5(5x-6)+23)=0

We add all the numbers together, and all the variables

4(+4x)-5x-(8+-5(5x-6)+23)+7=0

We add all the numbers together, and all the variables

-5x+4(+4x)-(8+-5(5x-6)+23)+7=0

We use the square of the difference formula

-5x+4(+4x)-(8-5(5x-6)+23)+7=0

We multiply parentheses

-5x+16x-(8-5(5x-6)+23)+7=0



We calculate terms in parentheses: -(8-5(5x-6)+23), so:

8-5(5x-6)+23

determiningTheFunctionDomain
-5(5x-6)+8+23

We add all the numbers together, and all the variables

-5(5x-6)+31

We multiply parentheses

-25x+30+31

We add all the numbers together, and all the variables

-25x+61

Back to the equation:

-(-25x+61)



We add all the numbers together, and all the variables

11x-(-25x+61)+7=0

We get rid of parentheses

11x+25x-61+7=0

We add all the numbers together, and all the variables

36x-54=0

We move all terms containing x to the left, all other terms to the right

36x=54

x=54/36

x=1+1/2

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