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4(3x+5)=6(1x+8)-1x
We move all terms to the left:
4(3x+5)-(6(1x+8)-1x)=0
We add all the numbers together, and all the variables
4(3x+5)-(6(x+8)-1x)=0
We multiply parentheses
12x-(6(x+8)-1x)+20=0
We calculate terms in parentheses: -(6(x+8)-1x), so:We get rid of parentheses
6(x+8)-1x
We add all the numbers together, and all the variables
-1x+6(x+8)
We multiply parentheses
-1x+6x+48
We add all the numbers together, and all the variables
5x+48
Back to the equation:
-(5x+48)
12x-5x-48+20=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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