4(3x+5)=-40+12

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Solution for 4(3x+5)=-40+12 equation: 



4(3x+5)=-40+12

We move all terms to the left:

4(3x+5)-(-40+12)=0

We add all the numbers together, and all the variables

4(3x+5)-(-28)=0

We add all the numbers together, and all the variables

4(3x+5)+28=0

We multiply parentheses

12x+20+28=0

We add all the numbers together, and all the variables

12x+48=0

We move all terms containing x to the left, all other terms to the right

12x=-48

x=-48/12

x=-4

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