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4(3x+4)=16x+13-4x+3
We move all terms to the left:
4(3x+4)-(16x+13-4x+3)=0
We add all the numbers together, and all the variables
4(3x+4)-(12x+16)=0
We multiply parentheses
12x-(12x+16)+16=0
We get rid of parentheses
12x-12x-16+16=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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