4(3x+3)+8(x+1)=56

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Solution for 4(3x+3)+8(x+1)=56 equation:


Simplifying
4(3x + 3) + 8(x + 1) = 56

Reorder the terms:
4(3 + 3x) + 8(x + 1) = 56
(3 * 4 + 3x * 4) + 8(x + 1) = 56
(12 + 12x) + 8(x + 1) = 56

Reorder the terms:
12 + 12x + 8(1 + x) = 56
12 + 12x + (1 * 8 + x * 8) = 56
12 + 12x + (8 + 8x) = 56

Reorder the terms:
12 + 8 + 12x + 8x = 56

Combine like terms: 12 + 8 = 20
20 + 12x + 8x = 56

Combine like terms: 12x + 8x = 20x
20 + 20x = 56

Solving
20 + 20x = 56

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 20x = 56 + -20

Combine like terms: 20 + -20 = 0
0 + 20x = 56 + -20
20x = 56 + -20

Combine like terms: 56 + -20 = 36
20x = 36

Divide each side by '20'.
x = 1.8

Simplifying
x = 1.8

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