4(3x+2)+5x+1=-3(6x-5)+4-8x

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Solution for 4(3x+2)+5x+1=-3(6x-5)+4-8x equation: 



4(3x+2)+5x+1=-3(6x-5)+4-8x

We move all terms to the left:

4(3x+2)+5x+1-(-3(6x-5)+4-8x)=0

We add all the numbers together, and all the variables

5x+4(3x+2)-(-3(6x-5)+4-8x)+1=0

We multiply parentheses

5x+12x-(-3(6x-5)+4-8x)+8+1=0



We calculate terms in parentheses: -(-3(6x-5)+4-8x), so:

-3(6x-5)+4-8x

determiningTheFunctionDomain
-3(6x-5)-8x+4

We add all the numbers together, and all the variables

-8x-3(6x-5)+4

We multiply parentheses

-8x-18x+15+4

We add all the numbers together, and all the variables

-26x+19

Back to the equation:

-(-26x+19)



We add all the numbers together, and all the variables

17x-(-26x+19)+9=0

We get rid of parentheses

17x+26x-19+9=0

We add all the numbers together, and all the variables

43x-10=0

We move all terms containing x to the left, all other terms to the right

43x=10

x=10/43

x=10/43

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