4(3x+12)=4(x-4)

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Solution for 4(3x+12)=4(x-4) equation: 



4(3x+12)=4(x-4)

We move all terms to the left:

4(3x+12)-(4(x-4))=0

We multiply parentheses

12x-(4(x-4))+48=0



We calculate terms in parentheses: -(4(x-4)), so:

4(x-4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

12x-4x+16+48=0

We add all the numbers together, and all the variables

8x+64=0

We move all terms containing x to the left, all other terms to the right

8x=-64

x=-64/8

x=-8

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