4(3x+12)+4(x+4)=16

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Solution for 4(3x+12)+4(x+4)=16 equation:


Simplifying
4(3x + 12) + 4(x + 4) = 16

Reorder the terms:
4(12 + 3x) + 4(x + 4) = 16
(12 * 4 + 3x * 4) + 4(x + 4) = 16
(48 + 12x) + 4(x + 4) = 16

Reorder the terms:
48 + 12x + 4(4 + x) = 16
48 + 12x + (4 * 4 + x * 4) = 16
48 + 12x + (16 + 4x) = 16

Reorder the terms:
48 + 16 + 12x + 4x = 16

Combine like terms: 48 + 16 = 64
64 + 12x + 4x = 16

Combine like terms: 12x + 4x = 16x
64 + 16x = 16

Solving
64 + 16x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-64' to each side of the equation.
64 + -64 + 16x = 16 + -64

Combine like terms: 64 + -64 = 0
0 + 16x = 16 + -64
16x = 16 + -64

Combine like terms: 16 + -64 = -48
16x = -48

Divide each side by '16'.
x = -3

Simplifying
x = -3

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