4(3x+10)=2(4x-8)+20

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Solution for 4(3x+10)=2(4x-8)+20 equation:


Simplifying
4(3x + 10) = 2(4x + -8) + 20

Reorder the terms:
4(10 + 3x) = 2(4x + -8) + 20
(10 * 4 + 3x * 4) = 2(4x + -8) + 20
(40 + 12x) = 2(4x + -8) + 20

Reorder the terms:
40 + 12x = 2(-8 + 4x) + 20
40 + 12x = (-8 * 2 + 4x * 2) + 20
40 + 12x = (-16 + 8x) + 20

Reorder the terms:
40 + 12x = -16 + 20 + 8x

Combine like terms: -16 + 20 = 4
40 + 12x = 4 + 8x

Solving
40 + 12x = 4 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
40 + 12x + -8x = 4 + 8x + -8x

Combine like terms: 12x + -8x = 4x
40 + 4x = 4 + 8x + -8x

Combine like terms: 8x + -8x = 0
40 + 4x = 4 + 0
40 + 4x = 4

Add '-40' to each side of the equation.
40 + -40 + 4x = 4 + -40

Combine like terms: 40 + -40 = 0
0 + 4x = 4 + -40
4x = 4 + -40

Combine like terms: 4 + -40 = -36
4x = -36

Divide each side by '4'.
x = -9

Simplifying
x = -9

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