4(3x+1)=6-x

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Solution for 4(3x+1)=6-x equation: 



4(3x+1)=6-x

We move all terms to the left:

4(3x+1)-(6-x)=0

We add all the numbers together, and all the variables

4(3x+1)-(-1x+6)=0

We multiply parentheses

12x-(-1x+6)+4=0

We get rid of parentheses

12x+1x-6+4=0

We add all the numbers together, and all the variables

13x-2=0

We move all terms containing x to the left, all other terms to the right

13x=2

x=2/13

x=2/13

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