4(3x+1)+3(x+3)=28

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Solution for 4(3x+1)+3(x+3)=28 equation:


Simplifying
4(3x + 1) + 3(x + 3) = 28

Reorder the terms:
4(1 + 3x) + 3(x + 3) = 28
(1 * 4 + 3x * 4) + 3(x + 3) = 28
(4 + 12x) + 3(x + 3) = 28

Reorder the terms:
4 + 12x + 3(3 + x) = 28
4 + 12x + (3 * 3 + x * 3) = 28
4 + 12x + (9 + 3x) = 28

Reorder the terms:
4 + 9 + 12x + 3x = 28

Combine like terms: 4 + 9 = 13
13 + 12x + 3x = 28

Combine like terms: 12x + 3x = 15x
13 + 15x = 28

Solving
13 + 15x = 28

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 15x = 28 + -13

Combine like terms: 13 + -13 = 0
0 + 15x = 28 + -13
15x = 28 + -13

Combine like terms: 28 + -13 = 15
15x = 15

Divide each side by '15'.
x = 1

Simplifying
x = 1

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