4(3u+2)(u+3)/32(u-7)(3u+2)

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Solution for 4(3u+2)(u+3)/32(u-7)(3u+2) equation: 


u in (-oo:+oo)

((4*(3*u+2)*(u+3))/32)*(u-7)*(3*u+2) = 0

(4*(3*u+2)^2*(u+3)*(u-7))/32 = 0

( 3*u+2 )

3*u+2 = 0 // - 2

3*u = -2 // : 3

u = -2/3

( u+3 )

u+3 = 0 // - 3

u = -3

( u-7 )

u-7 = 0 // + 7

u = 7

u in { -2/3, -2/3, -3, 7 }

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