4(3t+1)-7=t-(t+2)

Solution for 4(3t+1)-7=t-(t+2) equation:

Simplifying
4(3t + 1) + -7 = t + -1(t + 2)

Reorder the terms:
4(1 + 3t) + -7 = t + -1(t + 2)
(1 * 4 + 3t * 4) + -7 = t + -1(t + 2)
(4 + 12t) + -7 = t + -1(t + 2)

Reorder the terms:
4 + -7 + 12t = t + -1(t + 2)

Combine like terms: 4 + -7 = -3
-3 + 12t = t + -1(t + 2)

Reorder the terms:
-3 + 12t = t + -1(2 + t)
-3 + 12t = t + (2 * -1 + t * -1)
-3 + 12t = t + (-2 + -1t)

Reorder the terms:
-3 + 12t = -2 + t + -1t

Combine like terms: t + -1t = 0
-3 + 12t = -2 + 0
-3 + 12t = -2

Solving
-3 + 12t = -2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 12t = -2 + 3

Combine like terms: -3 + 3 = 0
0 + 12t = -2 + 3
12t = -2 + 3

Combine like terms: -2 + 3 = 1
12t = 1

Divide each side by '12'.
t = 0.08333333333

Simplifying
t = 0.08333333333