4(3r-4)=3(r+9)=2

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Solution for 4(3r-4)=3(r+9)=2 equation: 



4(3r-4)=3(r+9)=2

We move all terms to the left:

4(3r-4)-(3(r+9))=0

We multiply parentheses

12r-(3(r+9))-16=0



We calculate terms in parentheses: -(3(r+9)), so:

3(r+9)

We multiply parentheses

3r+27

Back to the equation:

-(3r+27)



We get rid of parentheses

12r-3r-27-16=0

We add all the numbers together, and all the variables

9r-43=0

We move all terms containing r to the left, all other terms to the right

9r=43

r=43/9

r=4+7/9

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