4(3n-4)-5(n+2)=2

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Solution for 4(3n-4)-5(n+2)=2 equation:


Simplifying
4(3n + -4) + -5(n + 2) = 2

Reorder the terms:
4(-4 + 3n) + -5(n + 2) = 2
(-4 * 4 + 3n * 4) + -5(n + 2) = 2
(-16 + 12n) + -5(n + 2) = 2

Reorder the terms:
-16 + 12n + -5(2 + n) = 2
-16 + 12n + (2 * -5 + n * -5) = 2
-16 + 12n + (-10 + -5n) = 2

Reorder the terms:
-16 + -10 + 12n + -5n = 2

Combine like terms: -16 + -10 = -26
-26 + 12n + -5n = 2

Combine like terms: 12n + -5n = 7n
-26 + 7n = 2

Solving
-26 + 7n = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '26' to each side of the equation.
-26 + 26 + 7n = 2 + 26

Combine like terms: -26 + 26 = 0
0 + 7n = 2 + 26
7n = 2 + 26

Combine like terms: 2 + 26 = 28
7n = 28

Divide each side by '7'.
n = 4

Simplifying
n = 4

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