4(3n-37)=8(n-1)

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Solution for 4(3n-37)=8(n-1) equation:



4(3n-37)=8(n-1)
We move all terms to the left:
4(3n-37)-(8(n-1))=0
We multiply parentheses
12n-(8(n-1))-148=0
We calculate terms in parentheses: -(8(n-1)), so:
8(n-1)
We multiply parentheses
8n-8
Back to the equation:
-(8n-8)
We get rid of parentheses
12n-8n+8-148=0
We add all the numbers together, and all the variables
4n-140=0
We move all terms containing n to the left, all other terms to the right
4n=140
n=140/4
n=35

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