4(3n-2)+6=4(2n-5)+2n

Solution for 4(3n-2)+6=4(2n-5)+2n equation:

4(3n-2)+6=4(2n-5)+2n

We move all terms to the left:

4(3n-2)+6-(4(2n-5)+2n)=0

We multiply parentheses

12n-(4(2n-5)+2n)-8+6=0


We calculate terms in parentheses: -(4(2n-5)+2n), so:

4(2n-5)+2n

We add all the numbers together, and all the variables

2n+4(2n-5)

We multiply parentheses

2n+8n-20

We add all the numbers together, and all the variables

10n-20

Back to the equation:

-(10n-20)


We add all the numbers together, and all the variables

12n-(10n-20)-2=0

We get rid of parentheses

12n-10n+20-2=0

We add all the numbers together, and all the variables

2n+18=0

We move all terms containing n to the left, all other terms to the right

2n=-18

n=-18/2

n=-9