4(3n+4)=7(4n+4)+1

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Solution for 4(3n+4)=7(4n+4)+1 equation: 



4(3n+4)=7(4n+4)+1

We move all terms to the left:

4(3n+4)-(7(4n+4)+1)=0

We multiply parentheses

12n-(7(4n+4)+1)+16=0



We calculate terms in parentheses: -(7(4n+4)+1), so:

7(4n+4)+1

We multiply parentheses

28n+28+1

We add all the numbers together, and all the variables

28n+29

Back to the equation:

-(28n+29)



We get rid of parentheses

12n-28n-29+16=0

We add all the numbers together, and all the variables

-16n-13=0

We move all terms containing n to the left, all other terms to the right

-16n=13

n=13/-16

n=-13/16

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