4(3n+4)=6(7n+2)+8

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Solution for 4(3n+4)=6(7n+2)+8 equation: 



4(3n+4)=6(7n+2)+8

We move all terms to the left:

4(3n+4)-(6(7n+2)+8)=0

We multiply parentheses

12n-(6(7n+2)+8)+16=0



We calculate terms in parentheses: -(6(7n+2)+8), so:

6(7n+2)+8

We multiply parentheses

42n+12+8

We add all the numbers together, and all the variables

42n+20

Back to the equation:

-(42n+20)



We get rid of parentheses

12n-42n-20+16=0

We add all the numbers together, and all the variables

-30n-4=0

We move all terms containing n to the left, all other terms to the right

-30n=4

n=4/-30

n=-2/15

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