4(3n+1)=6(8n+1)+7

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Solution for 4(3n+1)=6(8n+1)+7 equation: 



4(3n+1)=6(8n+1)+7

We move all terms to the left:

4(3n+1)-(6(8n+1)+7)=0

We multiply parentheses

12n-(6(8n+1)+7)+4=0



We calculate terms in parentheses: -(6(8n+1)+7), so:

6(8n+1)+7

We multiply parentheses

48n+6+7

We add all the numbers together, and all the variables

48n+13

Back to the equation:

-(48n+13)



We get rid of parentheses

12n-48n-13+4=0

We add all the numbers together, and all the variables

-36n-9=0

We move all terms containing n to the left, all other terms to the right

-36n=9

n=9/-36

n=-1/4

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