4(3m+1)-2(m+3)=3(m-4)+2m+7

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Solution for 4(3m+1)-2(m+3)=3(m-4)+2m+7 equation: 



4(3m+1)-2(m+3)=3(m-4)+2m+7

We move all terms to the left:

4(3m+1)-2(m+3)-(3(m-4)+2m+7)=0

We multiply parentheses

12m-2m-(3(m-4)+2m+7)+4-6=0



We calculate terms in parentheses: -(3(m-4)+2m+7), so:

3(m-4)+2m+7

We add all the numbers together, and all the variables

2m+3(m-4)+7

We multiply parentheses

2m+3m-12+7

We add all the numbers together, and all the variables

5m-5

Back to the equation:

-(5m-5)



We add all the numbers together, and all the variables

10m-(5m-5)-2=0

We get rid of parentheses

10m-5m+5-2=0

We add all the numbers together, and all the variables

5m+3=0

We move all terms containing m to the left, all other terms to the right

5m=-3

m=-3/5

m=-3/5

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