4(3k+2)=68

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Solution for 4(3k+2)=68 equation: 



4(3k+2)=68

We move all terms to the left:

4(3k+2)-(68)=0

We multiply parentheses

12k+8-68=0

We add all the numbers together, and all the variables

12k-60=0

We move all terms containing k to the left, all other terms to the right

12k=60

k=60/12

k=5

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