4(3i-2)=16i

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Solution for 4(3i-2)=16i equation: 



4(3i-2)=16i

We move all terms to the left:

4(3i-2)-(16i)=0

We add all the numbers together, and all the variables

-16i+4(3i-2)=0

We multiply parentheses

-16i+12i-8=0

We add all the numbers together, and all the variables

-4i-8=0

We move all terms containing i to the left, all other terms to the right

-4i=8

i=8/-4

i=-2

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