4(3i+2)-8=5(2i+3)+5

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Solution for 4(3i+2)-8=5(2i+3)+5 equation:



4(3i+2)-8=5(2i+3)+5
We move all terms to the left:
4(3i+2)-8-(5(2i+3)+5)=0
We multiply parentheses
12i-(5(2i+3)+5)+8-8=0
We calculate terms in parentheses: -(5(2i+3)+5), so:
5(2i+3)+5
We multiply parentheses
10i+15+5
We add all the numbers together, and all the variables
10i+20
Back to the equation:
-(10i+20)
We add all the numbers together, and all the variables
12i-(10i+20)=0
We get rid of parentheses
12i-10i-20=0
We add all the numbers together, and all the variables
2i-20=0
We move all terms containing i to the left, all other terms to the right
2i=20
i=20/2
i=10

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